Integrand size = 29, antiderivative size = 235 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {a^2 \left (7 a^4-10 a^2 b^2+3 b^4\right ) \log (a+b \sin (c+d x))}{b^8 d}-\frac {2 a \left (3 a^4-4 a^2 b^2+b^4\right ) \sin (c+d x)}{b^7 d}+\frac {\left (5 a^4-6 a^2 b^2+b^4\right ) \sin ^2(c+d x)}{2 b^6 d}-\frac {4 a \left (a^2-b^2\right ) \sin ^3(c+d x)}{3 b^5 d}+\frac {\left (3 a^2-2 b^2\right ) \sin ^4(c+d x)}{4 b^4 d}-\frac {2 a \sin ^5(c+d x)}{5 b^3 d}+\frac {\sin ^6(c+d x)}{6 b^2 d}+\frac {a^3 \left (a^2-b^2\right )^2}{b^8 d (a+b \sin (c+d x))} \]
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Time = 0.21 (sec) , antiderivative size = 235, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2916, 12, 962} \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=-\frac {4 a \left (a^2-b^2\right ) \sin ^3(c+d x)}{3 b^5 d}+\frac {\left (3 a^2-2 b^2\right ) \sin ^4(c+d x)}{4 b^4 d}+\frac {a^2 \left (7 a^4-10 a^2 b^2+3 b^4\right ) \log (a+b \sin (c+d x))}{b^8 d}-\frac {2 a \left (3 a^4-4 a^2 b^2+b^4\right ) \sin (c+d x)}{b^7 d}+\frac {\left (5 a^4-6 a^2 b^2+b^4\right ) \sin ^2(c+d x)}{2 b^6 d}+\frac {a^3 \left (a^2-b^2\right )^2}{b^8 d (a+b \sin (c+d x))}-\frac {2 a \sin ^5(c+d x)}{5 b^3 d}+\frac {\sin ^6(c+d x)}{6 b^2 d} \]
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Rule 12
Rule 962
Rule 2916
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x^3 \left (b^2-x^2\right )^2}{b^3 (a+x)^2} \, dx,x,b \sin (c+d x)\right )}{b^5 d} \\ & = \frac {\text {Subst}\left (\int \frac {x^3 \left (b^2-x^2\right )^2}{(a+x)^2} \, dx,x,b \sin (c+d x)\right )}{b^8 d} \\ & = \frac {\text {Subst}\left (\int \left (-2 a \left (3 a^4-4 a^2 b^2+b^4\right )+\left (5 a^4-6 a^2 b^2+b^4\right ) x-4 a \left (a^2-b^2\right ) x^2+\left (3 a^2-2 b^2\right ) x^3-2 a x^4+x^5-\frac {a^3 \left (a^2-b^2\right )^2}{(a+x)^2}+\frac {7 a^6-10 a^4 b^2+3 a^2 b^4}{a+x}\right ) \, dx,x,b \sin (c+d x)\right )}{b^8 d} \\ & = \frac {a^2 \left (7 a^4-10 a^2 b^2+3 b^4\right ) \log (a+b \sin (c+d x))}{b^8 d}-\frac {2 a \left (3 a^4-4 a^2 b^2+b^4\right ) \sin (c+d x)}{b^7 d}+\frac {\left (5 a^4-6 a^2 b^2+b^4\right ) \sin ^2(c+d x)}{2 b^6 d}-\frac {4 a \left (a^2-b^2\right ) \sin ^3(c+d x)}{3 b^5 d}+\frac {\left (3 a^2-2 b^2\right ) \sin ^4(c+d x)}{4 b^4 d}-\frac {2 a \sin ^5(c+d x)}{5 b^3 d}+\frac {\sin ^6(c+d x)}{6 b^2 d}+\frac {a^3 \left (a^2-b^2\right )^2}{b^8 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 1.41 (sec) , antiderivative size = 264, normalized size of antiderivative = 1.12 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {60 a^3 \left (a^2-b^2\right ) \left (a^2-b^2+\left (7 a^2-3 b^2\right ) \log (a+b \sin (c+d x))\right )+60 a^2 b \left (a^2-b^2\right ) \left (-6 a^2+2 b^2+\left (7 a^2-3 b^2\right ) \log (a+b \sin (c+d x))\right ) \sin (c+d x)-30 a b^2 \left (7 a^4-10 a^2 b^2+3 b^4\right ) \sin ^2(c+d x)+10 b^3 \left (7 a^4-10 a^2 b^2+3 b^4\right ) \sin ^3(c+d x)+\left (-35 a^3 b^4+50 a b^6\right ) \sin ^4(c+d x)+3 b^5 \left (7 a^2-10 b^2\right ) \sin ^5(c+d x)-14 a b^6 \sin ^6(c+d x)+10 b^7 \sin ^7(c+d x)}{60 b^8 d (a+b \sin (c+d x))} \]
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Time = 1.11 (sec) , antiderivative size = 249, normalized size of antiderivative = 1.06
method | result | size |
derivativedivides | \(\frac {-\frac {-\frac {\left (\sin ^{6}\left (d x +c \right )\right ) b^{5}}{6}+\frac {2 a \,b^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {3 a^{2} b^{3} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {b^{5} \left (\sin ^{4}\left (d x +c \right )\right )}{2}+\frac {4 b^{2} a^{3} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {4 a \,b^{4} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {5 a^{4} b \left (\sin ^{2}\left (d x +c \right )\right )}{2}+3 a^{2} b^{3} \left (\sin ^{2}\left (d x +c \right )\right )-\frac {b^{5} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+6 \sin \left (d x +c \right ) a^{5}-8 a^{3} b^{2} \sin \left (d x +c \right )+2 \sin \left (d x +c \right ) a \,b^{4}}{b^{7}}+\frac {a^{3} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}{b^{8} \left (a +b \sin \left (d x +c \right )\right )}+\frac {a^{2} \left (7 a^{4}-10 a^{2} b^{2}+3 b^{4}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{b^{8}}}{d}\) | \(249\) |
default | \(\frac {-\frac {-\frac {\left (\sin ^{6}\left (d x +c \right )\right ) b^{5}}{6}+\frac {2 a \,b^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {3 a^{2} b^{3} \left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {b^{5} \left (\sin ^{4}\left (d x +c \right )\right )}{2}+\frac {4 b^{2} a^{3} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {4 a \,b^{4} \left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {5 a^{4} b \left (\sin ^{2}\left (d x +c \right )\right )}{2}+3 a^{2} b^{3} \left (\sin ^{2}\left (d x +c \right )\right )-\frac {b^{5} \left (\sin ^{2}\left (d x +c \right )\right )}{2}+6 \sin \left (d x +c \right ) a^{5}-8 a^{3} b^{2} \sin \left (d x +c \right )+2 \sin \left (d x +c \right ) a \,b^{4}}{b^{7}}+\frac {a^{3} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )}{b^{8} \left (a +b \sin \left (d x +c \right )\right )}+\frac {a^{2} \left (7 a^{4}-10 a^{2} b^{2}+3 b^{4}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{b^{8}}}{d}\) | \(249\) |
parallelrisch | \(\frac {13440 \left (a +b \right ) \left (a +b \sin \left (d x +c \right )\right ) \left (a -b \right ) \left (a^{2}-\frac {3 b^{2}}{7}\right ) a^{2} \ln \left (2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )-13440 \left (a +b \right ) \left (a +b \sin \left (d x +c \right )\right ) \left (a -b \right ) \left (a^{2}-\frac {3 b^{2}}{7}\right ) a^{2} \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3360 a^{5} b^{2}-4240 a^{3} b^{4}+850 a \,b^{6}\right ) \cos \left (2 d x +2 c \right )+\left (-560 a^{4} b^{3}+590 a^{2} b^{5}-45 b^{7}\right ) \sin \left (3 d x +3 c \right )+\left (-140 a^{3} b^{4}+116 a \,b^{6}\right ) \cos \left (4 d x +4 c \right )+\left (42 a^{2} b^{5}-25 b^{7}\right ) \sin \left (5 d x +5 c \right )+14 a \,b^{6} \cos \left (6 d x +6 c \right )-5 b^{7} \sin \left (7 d x +7 c \right )+\left (-13440 a^{6} b +20880 a^{4} b^{3}-7740 a^{2} b^{5}+295 b^{7}\right ) \sin \left (d x +c \right )-3360 a^{5} b^{2}+4380 a^{3} b^{4}-980 a \,b^{6}}{1920 b^{8} d \left (a +b \sin \left (d x +c \right )\right )}\) | \(325\) |
risch | \(-\frac {\cos \left (4 d x +4 c \right )}{32 d \,b^{2}}+\frac {3 \cos \left (4 d x +4 c \right ) a^{2}}{32 d \,b^{4}}+\frac {a^{3} \sin \left (3 d x +3 c \right )}{3 b^{5} d}-\frac {5 a \sin \left (3 d x +3 c \right )}{24 b^{3} d}+\frac {3 i a^{5} {\mathrm e}^{i \left (d x +c \right )}}{b^{7} d}-\frac {7 i a^{3} {\mathrm e}^{i \left (d x +c \right )}}{2 b^{5} d}+\frac {5 i a \,{\mathrm e}^{i \left (d x +c \right )}}{8 b^{3} d}-\frac {3 i a^{5} {\mathrm e}^{-i \left (d x +c \right )}}{b^{7} d}+\frac {7 i a^{3} {\mathrm e}^{-i \left (d x +c \right )}}{2 b^{5} d}-\frac {5 i a \,{\mathrm e}^{-i \left (d x +c \right )}}{8 b^{3} d}-\frac {14 i a^{6} c}{b^{8} d}+\frac {20 i a^{4} c}{b^{6} d}-\frac {6 i a^{2} c}{b^{4} d}-\frac {\cos \left (6 d x +6 c \right )}{192 d \,b^{2}}+\frac {2 a^{3} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) {\mathrm e}^{i \left (d x +c \right )}}{b^{8} d \left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +2 a \,{\mathrm e}^{i \left (d x +c \right )}\right )}-\frac {a \sin \left (5 d x +5 c \right )}{40 b^{3} d}+\frac {7 a^{6} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right )}{b^{8} d}-\frac {10 a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right )}{b^{6} d}+\frac {3 a^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right )}{b^{4} d}+\frac {9 \,{\mathrm e}^{2 i \left (d x +c \right )} a^{2}}{16 b^{4} d}-\frac {5 \,{\mathrm e}^{-2 i \left (d x +c \right )} a^{4}}{8 b^{6} d}-\frac {5 \,{\mathrm e}^{2 i \left (d x +c \right )}}{128 b^{2} d}-\frac {5 \,{\mathrm e}^{-2 i \left (d x +c \right )}}{128 b^{2} d}+\frac {9 \,{\mathrm e}^{-2 i \left (d x +c \right )} a^{2}}{16 b^{4} d}-\frac {5 \,{\mathrm e}^{2 i \left (d x +c \right )} a^{4}}{8 b^{6} d}-\frac {7 i a^{6} x}{b^{8}}+\frac {10 i a^{4} x}{b^{6}}-\frac {3 i a^{2} x}{b^{4}}\) | \(601\) |
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Time = 0.41 (sec) , antiderivative size = 279, normalized size of antiderivative = 1.19 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {112 \, a b^{6} \cos \left (d x + c\right )^{6} + 480 \, a^{7} - 3240 \, a^{5} b^{2} + 3185 \, a^{3} b^{4} - 487 \, a b^{6} - 8 \, {\left (35 \, a^{3} b^{4} - 8 \, a b^{6}\right )} \cos \left (d x + c\right )^{4} + 16 \, {\left (105 \, a^{5} b^{2} - 115 \, a^{3} b^{4} + 16 \, a b^{6}\right )} \cos \left (d x + c\right )^{2} + 480 \, {\left (7 \, a^{7} - 10 \, a^{5} b^{2} + 3 \, a^{3} b^{4} + {\left (7 \, a^{6} b - 10 \, a^{4} b^{3} + 3 \, a^{2} b^{5}\right )} \sin \left (d x + c\right )\right )} \log \left (b \sin \left (d x + c\right ) + a\right ) - {\left (80 \, b^{7} \cos \left (d x + c\right )^{6} - 168 \, a^{2} b^{5} \cos \left (d x + c\right )^{4} + 2880 \, a^{6} b - 3800 \, a^{4} b^{3} + 1007 \, a^{2} b^{5} - 25 \, b^{7} + 16 \, {\left (35 \, a^{4} b^{3} - 29 \, a^{2} b^{5}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{480 \, {\left (b^{9} d \sin \left (d x + c\right ) + a b^{8} d\right )}} \]
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Timed out. \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 218, normalized size of antiderivative = 0.93 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {60 \, {\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )}}{b^{9} \sin \left (d x + c\right ) + a b^{8}} + \frac {10 \, b^{5} \sin \left (d x + c\right )^{6} - 24 \, a b^{4} \sin \left (d x + c\right )^{5} + 15 \, {\left (3 \, a^{2} b^{3} - 2 \, b^{5}\right )} \sin \left (d x + c\right )^{4} - 80 \, {\left (a^{3} b^{2} - a b^{4}\right )} \sin \left (d x + c\right )^{3} + 30 \, {\left (5 \, a^{4} b - 6 \, a^{2} b^{3} + b^{5}\right )} \sin \left (d x + c\right )^{2} - 120 \, {\left (3 \, a^{5} - 4 \, a^{3} b^{2} + a b^{4}\right )} \sin \left (d x + c\right )}{b^{7}} + \frac {60 \, {\left (7 \, a^{6} - 10 \, a^{4} b^{2} + 3 \, a^{2} b^{4}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{b^{8}}}{60 \, d} \]
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Time = 0.34 (sec) , antiderivative size = 300, normalized size of antiderivative = 1.28 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {60 \, {\left (7 \, a^{6} - 10 \, a^{4} b^{2} + 3 \, a^{2} b^{4}\right )} \log \left ({\left | b \sin \left (d x + c\right ) + a \right |}\right )}{b^{8}} - \frac {60 \, {\left (7 \, a^{6} b \sin \left (d x + c\right ) - 10 \, a^{4} b^{3} \sin \left (d x + c\right ) + 3 \, a^{2} b^{5} \sin \left (d x + c\right ) + 6 \, a^{7} - 8 \, a^{5} b^{2} + 2 \, a^{3} b^{4}\right )}}{{\left (b \sin \left (d x + c\right ) + a\right )} b^{8}} + \frac {10 \, b^{10} \sin \left (d x + c\right )^{6} - 24 \, a b^{9} \sin \left (d x + c\right )^{5} + 45 \, a^{2} b^{8} \sin \left (d x + c\right )^{4} - 30 \, b^{10} \sin \left (d x + c\right )^{4} - 80 \, a^{3} b^{7} \sin \left (d x + c\right )^{3} + 80 \, a b^{9} \sin \left (d x + c\right )^{3} + 150 \, a^{4} b^{6} \sin \left (d x + c\right )^{2} - 180 \, a^{2} b^{8} \sin \left (d x + c\right )^{2} + 30 \, b^{10} \sin \left (d x + c\right )^{2} - 360 \, a^{5} b^{5} \sin \left (d x + c\right ) + 480 \, a^{3} b^{7} \sin \left (d x + c\right ) - 120 \, a b^{9} \sin \left (d x + c\right )}{b^{12}}}{60 \, d} \]
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Time = 12.43 (sec) , antiderivative size = 375, normalized size of antiderivative = 1.60 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {{\sin \left (c+d\,x\right )}^3\,\left (\frac {2\,a^3}{3\,b^5}+\frac {2\,a\,\left (\frac {2}{b^2}-\frac {3\,a^2}{b^4}\right )}{3\,b}\right )}{d}-\frac {{\sin \left (c+d\,x\right )}^4\,\left (\frac {1}{2\,b^2}-\frac {3\,a^2}{4\,b^4}\right )}{d}+\frac {{\sin \left (c+d\,x\right )}^2\,\left (\frac {1}{2\,b^2}+\frac {a^2\,\left (\frac {2}{b^2}-\frac {3\,a^2}{b^4}\right )}{2\,b^2}-\frac {a\,\left (\frac {2\,a^3}{b^5}+\frac {2\,a\,\left (\frac {2}{b^2}-\frac {3\,a^2}{b^4}\right )}{b}\right )}{b}\right )}{d}-\frac {\sin \left (c+d\,x\right )\,\left (\frac {a^2\,\left (\frac {2\,a^3}{b^5}+\frac {2\,a\,\left (\frac {2}{b^2}-\frac {3\,a^2}{b^4}\right )}{b}\right )}{b^2}+\frac {2\,a\,\left (\frac {1}{b^2}+\frac {a^2\,\left (\frac {2}{b^2}-\frac {3\,a^2}{b^4}\right )}{b^2}-\frac {2\,a\,\left (\frac {2\,a^3}{b^5}+\frac {2\,a\,\left (\frac {2}{b^2}-\frac {3\,a^2}{b^4}\right )}{b}\right )}{b}\right )}{b}\right )}{d}+\frac {{\sin \left (c+d\,x\right )}^6}{6\,b^2\,d}-\frac {2\,a\,{\sin \left (c+d\,x\right )}^5}{5\,b^3\,d}+\frac {\ln \left (a+b\,\sin \left (c+d\,x\right )\right )\,\left (7\,a^6-10\,a^4\,b^2+3\,a^2\,b^4\right )}{b^8\,d}+\frac {a^7-2\,a^5\,b^2+a^3\,b^4}{b\,d\,\left (\sin \left (c+d\,x\right )\,b^8+a\,b^7\right )} \]
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